My YT scrapping does not apply to all the elements I want

#1

Hello community,

I'm writing to you today with a concern that I think is solvable.

I'm scrapping from this well known site: https://channelcrawler.com/fra/results2/733188/page:1 (and the following pages from it), in order to export me a spreadsheet containing all the YT channels and their information (especially the number of subscribers).

However, with the WebScraper tool, I manage to get out in CSV all the channels by their names but without the information OR all the information but without the names... which is very problematic! Indeed, when I select my elements, there are two different blocks, one for the name, one for the information, but I literally try to have a spreadsheet like :

Row 1 NameString1 InfoString1
line 2 StringName2 StringInfo2
etc.

I thank you in advance for helping me!

Sincerely,

Clément.

NB: I know very little about the tool; in fact, I tried to base myself on the following tutorial:

but I don't know if it fits my case

#2

@ClementRDS Hi, have you also checked the available learning resources within the ''Learn'' section?

Sitemap example:

{"_id":"channelcrawler-com","startUrl":["https://channelcrawler.com/fra/results2/733188/page:1"],"selectors":[{"id":"pagination","paginationType":"auto","parentSelectors":["_root","pagination"],"selector":".next a","type":"SelectorPagination"},{"delay":0,"id":"wrapper","multiple":true,"parentSelectors":["pagination"],"selector":"div.channel","type":"SelectorElement"},{"delay":0,"id":"name","multiple":false,"parentSelectors":["wrapper"],"regex":"","selector":"h4 a","type":"SelectorText"},{"delay":0,"id":"description","multiple":false,"parentSelectors":["wrapper"],"regex":"","selector":"p:nth-of-type(1) small","type":"SelectorText"}]}

#3

No, I am really starting from scratch with this tool... Knowing my wish and my problem, what steps should I take to get the desired CSV file...? Thank you again sir.